133010442511 has 4 divisors (see below), whose sum is σ = 133501256224. Its totient is φ = 132519628800.

The previous prime is 133010442503. The next prime is 133010442569. The reversal of 133010442511 is 115244010331.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 115244010331 = 61 ⋅1889246071.

It is a cyclic number.

It is not a de Polignac number, because 133010442511 - 2³ = 133010442503 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133010442581) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245406450 + ... + 245406991.

It is an arithmetic number, because the mean of its divisors is an integer number (33375314056).

Almost surely, 2^133010442511 is an apocalyptic number.

133010442511 is a deficient number, since it is larger than the sum of its proper divisors (490813713).

133010442511 is an equidigital number, since it uses as much as digits as its factorization.

133010442511 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 490813712.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 133010442511 its reverse (115244010331), we get a palindrome (248254452842).

The spelling of 133010442511 in words is "one hundred thirty-three billion, ten million, four hundred forty-two thousand, five hundred eleven".