133011100020031 has 4 divisors (see below), whose sum is σ = 133059626509464. Its totient is φ = 132962573530600.

The previous prime is 133011100020013. The next prime is 133011100020041. The reversal of 133011100020031 is 130020001110331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133011100020031 - 2⁵ = 133011100019999 is a prime.

It is a super-2 number, since 2×133011100020031² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133011100019987 and 133011100020014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133011100020041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24263240605 + ... + 24263246086.

It is an arithmetic number, because the mean of its divisors is an integer number (33264906627366).

Almost surely, 2^{133011100020031} is an apocalyptic number.

133011100020031 is a deficient number, since it is larger than the sum of its proper divisors (48526489433).

133011100020031 is an equidigital number, since it uses as much as digits as its factorization.

133011100020031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48526489432.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 133011100020031 its reverse (130020001110331), we get a palindrome (263031101130362).

The spelling of 133011100020031 in words is "one hundred thirty-three trillion, eleven billion, one hundred million, twenty thousand, thirty-one".