133011119 has 2 divisors, whose sum is σ = 133011120. Its totient is φ = 133011118.

The previous prime is 133011113. The next prime is 133011133. The reversal of 133011119 is 911110331.

It is a weak prime.

It is an emirp because it is prime and its reverse (911110331) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133011119 is a prime.

It is a super-2 number, since 2×133011119² = 35383915555264322, which contains 22 as substring.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133011119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133011113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505559 + 66505560.

It is an arithmetic number, because the mean of its divisors is an integer number (66505560).

Almost surely, 2^133011119 is an apocalyptic number.

133011119 is a deficient number, since it is larger than the sum of its proper divisors (1).

133011119 is an equidigital number, since it uses as much as digits as its factorization.

133011119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81, while the sum is 20.

The square root of 133011119 is about 11533.0446543833. The cubic root of 133011119 is about 510.4610965125.

The spelling of 133011119 in words is "one hundred thirty-three million, eleven thousand, one hundred nineteen".