133011130020041 has 32 divisors (see below), whose sum is σ = 170826717132288. Its totient is φ = 100662139353600.

The previous prime is 133011130019981. The next prime is 133011130020173. The reversal of 133011130020041 is 140020031110331.

It is a cyclic number.

It is not a de Polignac number, because 133011130020041 - 2¹⁰ = 133011130019017 is a prime.

It is a super-3 number, since 3×133011130020041³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 133011130019995 and 133011130020022.

It is not an unprimeable number, because it can be changed into a prime (133011130022041) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 122740325 + ... + 123819261.

It is an arithmetic number, because the mean of its divisors is an integer number (5338334910384).

Almost surely, 2^{133011130020041} is an apocalyptic number.

It is an amenable number.

133011130020041 is a deficient number, since it is larger than the sum of its proper divisors (37815587112247).

133011130020041 is a wasteful number, since it uses less digits than its factorization.

133011130020041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1137881.

The product of its (nonzero) digits is 216, while the sum is 20.

Adding to 133011130020041 its reverse (140020031110331), we get a palindrome (273031161130372).

The spelling of 133011130020041 in words is "one hundred thirty-three trillion, eleven billion, one hundred thirty million, twenty thousand, forty-one".