Base | Representation |
---|---|
bin | 10011010110110000110… |
… | …111011111100000010011 |
3 | 11201011020210211022012101 |
4 | 103112300313133200103 |
5 | 133243032212401233 |
6 | 2455013425141231 |
7 | 165045264264532 |
oct | 23266067374023 |
9 | 4634223738171 |
10 | 1330112231443 |
11 | 473108751386 |
12 | 19594ba8a817 |
13 | 985767c6478 |
14 | 4854088a319 |
15 | 248ec81cc7d |
hex | 135b0ddf813 |
1330112231443 has 2 divisors, whose sum is σ = 1330112231444. Its totient is φ = 1330112231442.
The previous prime is 1330112231429. The next prime is 1330112231471. The reversal of 1330112231443 is 3441322110331.
It is an a-pointer prime, because the next prime (1330112231471) can be obtained adding 1330112231443 to its sum of digits (28).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330112231443 - 25 = 1330112231411 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330112231143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665056115721 + 665056115722.
It is an arithmetic number, because the mean of its divisors is an integer number (665056115722).
Almost surely, 21330112231443 is an apocalyptic number.
1330112231443 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330112231443 is an equidigital number, since it uses as much as digits as its factorization.
1330112231443 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 1330112231443 its reverse (3441322110331), we get a palindrome (4771434341774).
The spelling of 1330112231443 in words is "one trillion, three hundred thirty billion, one hundred twelve million, two hundred thirty-one thousand, four hundred forty-three".
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