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1330113202021 is a prime number
BaseRepresentation
bin10011010110110000111…
…011001100011101100101
311201011020212122121120201
4103112300323030131211
5133243032434431041
62455013502030501
7165045305446312
oct23266073143545
94634225577521
101330113202021
1147310925460a
12195950278431
1398576a76186
1448540a5dd09
15248ec960631
hex135b0ecc765

1330113202021 has 2 divisors, whose sum is σ = 1330113202022. Its totient is φ = 1330113202020.

The previous prime is 1330113202013. The next prime is 1330113202043. The reversal of 1330113202021 is 1202023110331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1162431141921 + 167682060100 = 1078161^2 + 409490^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330113202021 - 23 = 1330113202013 is a prime.

It is a super-2 number, since 2×13301132020212 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1330113202021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330113202001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665056601010 + 665056601011.

It is an arithmetic number, because the mean of its divisors is an integer number (665056601011).

Almost surely, 21330113202021 is an apocalyptic number.

It is an amenable number.

1330113202021 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330113202021 is an equidigital number, since it uses as much as digits as its factorization.

1330113202021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 1330113202021 its reverse (1202023110331), we get a palindrome (2532136312352).

The spelling of 1330113202021 in words is "one trillion, three hundred thirty billion, one hundred thirteen million, two hundred two thousand, twenty-one".