Base | Representation |
---|---|
bin | 1100000110001110100100… |
… | …1111111100111001011111 |
3 | 1202002120112202112012101000 |
4 | 3001203221033330321133 |
5 | 3220411204244140333 |
6 | 44142242232521343 |
7 | 2541655310504565 |
oct | 301435117747137 |
9 | 52076482465330 |
10 | 13301132021343 |
11 | 4268a842a2421 |
12 | 15a9a22250253 |
13 | 7563a3199a2a |
14 | 33dac763da35 |
15 | 180ed6404713 |
hex | c18e93fce5f |
13301132021343 has 8 divisors (see below), whose sum is σ = 19705380772400. Its totient is φ = 8867421347544.
The previous prime is 13301132021297. The next prime is 13301132021363. The reversal of 13301132021343 is 34312023110331.
13301132021343 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 113 + 202 + 1 + 343 = 666.
It is not a de Polignac number, because 13301132021343 - 29 = 13301132020831 is a prime.
It is a super-2 number, since 2×133011320213432 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 492634519309 = 13301132021343 / (1 + 3 + 3 + 0 + 1 + 1 + 3 + 2 + 0 + 2 + 1 + 3 + 4 + 3).
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13301132021363) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 246317259628 + ... + 246317259681.
It is an arithmetic number, because the mean of its divisors is an integer number (2463172596550).
Almost surely, 213301132021343 is an apocalyptic number.
13301132021343 is a deficient number, since it is larger than the sum of its proper divisors (6404248751057).
13301132021343 is an equidigital number, since it uses as much as digits as its factorization.
13301132021343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 492634519318 (or 492634519312 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 13301132021343 its reverse (34312023110331), we get a palindrome (47613155131674).
The spelling of 13301132021343 in words is "thirteen trillion, three hundred one billion, one hundred thirty-two million, twenty-one thousand, three hundred forty-three".
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