Base | Representation |
---|---|
bin | 11110001111100100100001… |
… | …111010101101110100110011 |
3 | 122102221202200221112002222012 |
4 | 132033210201322231310303 |
5 | 114413224332233330003 |
6 | 1150520333155433135 |
7 | 40005520523624645 |
oct | 3617444172556463 |
9 | 572852627462865 |
10 | 133011411230003 |
11 | 394219060479a9 |
12 | 12b026045b57ab |
13 | 592abcb283697 |
14 | 24bbb02810895 |
15 | 1059deaa0c8d8 |
hex | 78f921eadd33 |
133011411230003 has 2 divisors, whose sum is σ = 133011411230004. Its totient is φ = 133011411230002.
The previous prime is 133011411229927. The next prime is 133011411230119. The reversal of 133011411230003 is 300032114110331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133011411230003 - 28 = 133011411229747 is a prime.
It is not a weakly prime, because it can be changed into another prime (133011411230903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66505705615001 + 66505705615002.
It is an arithmetic number, because the mean of its divisors is an integer number (66505705615002).
Almost surely, 2133011411230003 is an apocalyptic number.
133011411230003 is a deficient number, since it is larger than the sum of its proper divisors (1).
133011411230003 is an equidigital number, since it uses as much as digits as its factorization.
133011411230003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 133011411230003 its reverse (300032114110331), we get a palindrome (433043525340334).
The spelling of 133011411230003 in words is "one hundred thirty-three trillion, eleven billion, four hundred eleven million, two hundred thirty thousand, three".
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