13301201311217 has 2 divisors, whose sum is σ = 13301201311218. Its totient is φ = 13301201311216.

The previous prime is 13301201311207. The next prime is 13301201311219. The reversal of 13301201311217 is 71211310210331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6878403174241 + 6422798136976 = 2622671^2 + 2534324^2 .

It is a cyclic number.

It is not a de Polignac number, because 13301201311217 - 2¹⁰ = 13301201310193 is a prime.

Together with 13301201311219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13301201311219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650600655608 + 6650600655609.

It is an arithmetic number, because the mean of its divisors is an integer number (6650600655609).

Almost surely, 2^{13301201311217} is an apocalyptic number.

It is an amenable number.

13301201311217 is a deficient number, since it is larger than the sum of its proper divisors (1).

13301201311217 is an equidigital number, since it uses as much as digits as its factorization.

13301201311217 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 26.

Adding to 13301201311217 its reverse (71211310210331), we get a palindrome (84512511521548).

The spelling of 13301201311217 in words is "thirteen trillion, three hundred one billion, two hundred one million, three hundred eleven thousand, two hundred seventeen".