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133012020220111 = 314290710329681
BaseRepresentation
bin11110001111100101000110…
…001101110101000011001111
3122102221211021101110000100101
4132033211012031311003033
5114413232104134020421
61150520513432311531
740005541600146214
oct3617450615650317
9572854241400311
10133012020220111
113942209888620a
1212b027545425a7
13592ac974a9266
1424bbb5d657b0b
151059e34204191
hex78f9463750cf

133012020220111 has 4 divisors (see below), whose sum is σ = 137302730549824. Its totient is φ = 128721309890400.

The previous prime is 133012020220099. The next prime is 133012020220147. The reversal of 133012020220111 is 111022020210331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133012020220111 - 221 = 133012018122959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133012020220811) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2145355164810 + ... + 2145355164871.

It is an arithmetic number, because the mean of its divisors is an integer number (34325682637456).

Almost surely, 2133012020220111 is an apocalyptic number.

133012020220111 is a deficient number, since it is larger than the sum of its proper divisors (4290710329713).

133012020220111 is an equidigital number, since it uses as much as digits as its factorization.

133012020220111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4290710329712.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 133012020220111 its reverse (111022020210331), we get a palindrome (244034040430442).

The spelling of 133012020220111 in words is "one hundred thirty-three trillion, twelve billion, twenty million, two hundred twenty thousand, one hundred eleven".

Divisors: 1 31 4290710329681 133012020220111