133012352510535 has 32 divisors (see below), whose sum is σ = 214708814346240. Its totient is φ = 70310271170048.

The previous prime is 133012352510449. The next prime is 133012352510549. The reversal of 133012352510535 is 535015253210331.

It is a cyclic number.

It is not a de Polignac number, because 133012352510535 - 2⁷ = 133012352510407 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133012352510493 and 133012352510502.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 64147126 + ... + 66188204.

It is an arithmetic number, because the mean of its divisors is an integer number (6709650448320).

Almost surely, 2^{133012352510535} is an apocalyptic number.

133012352510535 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

133012352510535 is a deficient number, since it is larger than the sum of its proper divisors (81696461835705).

133012352510535 is a wasteful number, since it uses less digits than its factorization.

133012352510535 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2079647.

The product of its (nonzero) digits is 202500, while the sum is 39.

The spelling of 133012352510535 in words is "one hundred thirty-three trillion, twelve billion, three hundred fifty-two million, five hundred ten thousand, five hundred thirty-five".