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13301334011002 = 26650667005501
BaseRepresentation
bin1100000110001111010101…
…0010011110110001111010
31202002121001211121100002111
43001203311102132301322
53220412113001323002
644142314250122534
72541663312416662
oct301436522366172
952077054540074
1013301334011002
114269078314224
1215a9a79a2044a
13756405c9c83b
1433db063bd1a2
15180ee90033d7
hexc18f549ec7a

13301334011002 has 4 divisors (see below), whose sum is σ = 19952001016506. Its totient is φ = 6650667005500.

The previous prime is 13301334010997. The next prime is 13301334011003. The reversal of 13301334011002 is 20011043310331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 13130774096881 + 170559914121 = 3623641^2 + 412989^2 .

It is not an unprimeable number, because it can be changed into a prime (13301334011003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325333502749 + ... + 3325333502752.

Almost surely, 213301334011002 is an apocalyptic number.

13301334011002 is a deficient number, since it is larger than the sum of its proper divisors (6650667005504).

13301334011002 is an equidigital number, since it uses as much as digits as its factorization.

13301334011002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6650667005503.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 13301334011002 its reverse (20011043310331), we get a palindrome (33312377321333).

The spelling of 13301334011002 in words is "thirteen trillion, three hundred one billion, three hundred thirty-four million, eleven thousand, two".

Divisors: 1 2 6650667005501 13301334011002