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1330140220034 = 21814336657119
BaseRepresentation
bin10011010110110010100…
…010010000101010000010
311201011022202111021022212
4103112302202100222002
5133243111344020114
62455020305102122
7165046054215113
oct23266242205202
94634282437285
101330140220034
1147312252864a
12195959327942
139857c545a72
144854449420a
15248eeeeab3e
hex135b2890a82

1330140220034 has 8 divisors (see below), whose sum is σ = 1995320355840. Its totient is φ = 665033434756.

The previous prime is 1330140220033. The next prime is 1330140220051. The reversal of 1330140220034 is 4300220410331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×13301402200342 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1330140219991 and 1330140220009.

It is not an unprimeable number, because it can be changed into a prime (1330140220033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 18292274 + ... + 18364845.

It is an arithmetic number, because the mean of its divisors is an integer number (249415044480).

Almost surely, 21330140220034 is an apocalyptic number.

1330140220034 is a deficient number, since it is larger than the sum of its proper divisors (665180135806).

1330140220034 is a wasteful number, since it uses less digits than its factorization.

1330140220034 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 36675264.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 1330140220034 its reverse (4300220410331), we get a palindrome (5630360630365).

The spelling of 1330140220034 in words is "one trillion, three hundred thirty billion, one hundred forty million, two hundred twenty thousand, thirty-four".

Divisors: 1 2 18143 36286 36657119 73314238 665070110017 1330140220034