Base | Representation |
---|---|
bin | 1100000110001111100111… |
… | …0101100101101001010111 |
3 | 1202002121021011012101111221 |
4 | 3001203321311211221113 |
5 | 3220412242020314111 |
6 | 44142330013511211 |
7 | 2541665230153015 |
oct | 301437165455127 |
9 | 52077234171457 |
10 | 13301410323031 |
11 | 42691073a6616 |
12 | 15a9a9b4a2507 |
13 | 756418a3b39c |
14 | 33db125a58b5 |
15 | 181000a79371 |
hex | c18f9d65a57 |
13301410323031 has 2 divisors, whose sum is σ = 13301410323032. Its totient is φ = 13301410323030.
The previous prime is 13301410322971. The next prime is 13301410323043. The reversal of 13301410323031 is 13032301410331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13301410323031 - 217 = 13301410191959 is a prime.
It is a super-2 number, since 2×133014103230312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13301410322987 and 13301410323005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13301410324031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6650705161515 + 6650705161516.
It is an arithmetic number, because the mean of its divisors is an integer number (6650705161516).
Almost surely, 213301410323031 is an apocalyptic number.
13301410323031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13301410323031 is an equidigital number, since it uses as much as digits as its factorization.
13301410323031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13301410323031 its reverse (13032301410331), we get a palindrome (26333711733362).
The spelling of 13301410323031 in words is "thirteen trillion, three hundred one billion, four hundred ten million, three hundred twenty-three thousand, thirty-one".
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