Base | Representation |
---|---|
bin | 10011010110110011001… |
… | …100101001001100000001 |
3 | 11201011100112101202002212 |
4 | 103112303030221030001 |
5 | 133243122220034221 |
6 | 2455021343151505 |
7 | 165046250521244 |
oct | 23266314511401 |
9 | 4634315352085 |
10 | 1330151330561 |
11 | 4731288270a9 |
12 | 195960ba5595 |
13 | 98581935c41 |
14 | 48545b4725b |
15 | 24900e92b5b |
hex | 135b3329301 |
1330151330561 has 2 divisors, whose sum is σ = 1330151330562. Its totient is φ = 1330151330560.
The previous prime is 1330151330531. The next prime is 1330151330591. The reversal of 1330151330561 is 1650331510331.
It is a balanced prime because it is at equal distance from previous prime (1330151330531) and next prime (1330151330591).
It can be written as a sum of positive squares in only one way, i.e., 1236488400625 + 93662929936 = 1111975^2 + 306044^2 .
It is a cyclic number.
It is not a de Polignac number, because 1330151330561 - 210 = 1330151329537 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330151330531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665075665280 + 665075665281.
It is an arithmetic number, because the mean of its divisors is an integer number (665075665281).
Almost surely, 21330151330561 is an apocalyptic number.
It is an amenable number.
1330151330561 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330151330561 is an equidigital number, since it uses as much as digits as its factorization.
1330151330561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12150, while the sum is 32.
Adding to 1330151330561 its reverse (1650331510331), we get a palindrome (2980482840892).
The spelling of 1330151330561 in words is "one trillion, three hundred thirty billion, one hundred fifty-one million, three hundred thirty thousand, five hundred sixty-one".
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