Base | Representation |
---|---|
bin | 10011010110110100000… |
… | …101110110000100000111 |
3 | 11201011101120121120022101 |
4 | 103112310011312010013 |
5 | 133243140034404021 |
6 | 2455023040412531 |
7 | 165046522133302 |
oct | 23266405660407 |
9 | 4634346546271 |
10 | 1330166325511 |
11 | 473136239021 |
12 | 195966017147 |
13 | 98584a861aa |
14 | 48547b2bb39 |
15 | 24902455a91 |
hex | 135b4176107 |
1330166325511 has 2 divisors, whose sum is σ = 1330166325512. Its totient is φ = 1330166325510.
The previous prime is 1330166325493. The next prime is 1330166325533. The reversal of 1330166325511 is 1155236610331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1330166325511 - 217 = 1330166194439 is a prime.
It is a super-2 number, since 2×13301663255112 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1330166325611) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665083162755 + 665083162756.
It is an arithmetic number, because the mean of its divisors is an integer number (665083162756).
Almost surely, 21330166325511 is an apocalyptic number.
1330166325511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330166325511 is an equidigital number, since it uses as much as digits as its factorization.
1330166325511 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48600, while the sum is 37.
The spelling of 1330166325511 in words is "one trillion, three hundred thirty billion, one hundred sixty-six million, three hundred twenty-five thousand, five hundred eleven".
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