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133020344206153 is a prime number
BaseRepresentation
bin11110001111101100110110…
…010111010100001101001001
3122102222121202111111022112201
4132033230312113110031021
5114413401131104044103
61150524411424240201
740006255063646125
oct3617546627241511
9572877674438481
10133020344206153
113942567a520118
1212b04298170061
13592b9c2b979a1
1424bc30cd7a585
15105a26ed9a51d
hex78fb365d4349

133020344206153 has 2 divisors, whose sum is σ = 133020344206154. Its totient is φ = 133020344206152.

The previous prime is 133020344206097. The next prime is 133020344206159. The reversal of 133020344206153 is 351602443020331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 132300420804864 + 719923401289 = 11502192^2 + 848483^2 .

It is an emirp because it is prime and its reverse (351602443020331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133020344206153 - 29 = 133020344205641 is a prime.

It is not a weakly prime, because it can be changed into another prime (133020344206159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510172103076 + 66510172103077.

It is an arithmetic number, because the mean of its divisors is an integer number (66510172103077).

Almost surely, 2133020344206153 is an apocalyptic number.

It is an amenable number.

133020344206153 is a deficient number, since it is larger than the sum of its proper divisors (1).

133020344206153 is an equidigital number, since it uses as much as digits as its factorization.

133020344206153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 155520, while the sum is 37.

Adding to 133020344206153 its reverse (351602443020331), we get a palindrome (484622787226484).

The spelling of 133020344206153 in words is "one hundred thirty-three trillion, twenty billion, three hundred forty-four million, two hundred six thousand, one hundred fifty-three".