1330204020331 has 4 divisors (see below), whose sum is σ = 1361138997592. Its totient is φ = 1299269043072.

The previous prime is 1330204020323. The next prime is 1330204020391.

1330204020331 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1330204020331 - 2³ = 1330204020323 is a prime.

It is a super-2 number, since 2×1330204020331² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1330204020311) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15467488566 + ... + 15467488651.

It is an arithmetic number, because the mean of its divisors is an integer number (340284749398).

Almost surely, 2^{1330204020331} is an apocalyptic number.

1330204020331 is a deficient number, since it is larger than the sum of its proper divisors (30934977261).

1330204020331 is an equidigital number, since it uses as much as digits as its factorization.

1330204020331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 30934977260.

The product of its (nonzero) digits is 1296, while the sum is 22.

The spelling of 1330204020331 in words is "one trillion, three hundred thirty billion, two hundred four million, twenty thousand, three hundred thirty-one".