Base | Representation |
---|---|
bin | 11110001111101101000001… |
… | …110100110110111100111111 |
3 | 122102222122020220022212011012 |
4 | 132033231001310312330333 |
5 | 114413402024321000111 |
6 | 1150524442453545435 |
7 | 40006262620266515 |
oct | 3617550164667477 |
9 | 572878226285135 |
10 | 133020536500031 |
11 | 3942576901a384 |
12 | 12b0433064527b |
13 | 592ba2398454b |
14 | 24bc32a7144b5 |
15 | 105a281bd148b |
hex | 78fb41d36f3f |
133020536500031 has 2 divisors, whose sum is σ = 133020536500032. Its totient is φ = 133020536500030.
The previous prime is 133020536500003. The next prime is 133020536500127. The reversal of 133020536500031 is 130005635020331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133020536500031 - 210 = 133020536499007 is a prime.
It is a super-2 number, since 2×1330205365000312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133020536500231) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510268250015 + 66510268250016.
It is an arithmetic number, because the mean of its divisors is an integer number (66510268250016).
Almost surely, 2133020536500031 is an apocalyptic number.
133020536500031 is a deficient number, since it is larger than the sum of its proper divisors (1).
133020536500031 is an equidigital number, since it uses as much as digits as its factorization.
133020536500031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24300, while the sum is 32.
The spelling of 133020536500031 in words is "one hundred thirty-three trillion, twenty billion, five hundred thirty-six million, five hundred thousand, thirty-one".
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