Base | Representation |
---|---|
bin | 11110001111101101001000… |
… | …001000101010100000101011 |
3 | 122102222122112021111212012121 |
4 | 132033231020020222200223 |
5 | 114413402233420331433 |
6 | 1150524501154452111 |
7 | 40006265344116346 |
oct | 3617551010524053 |
9 | 572878467455177 |
10 | 133020642355243 |
11 | 3942581284aa25 |
12 | 12b0435bb94037 |
13 | 592ba3c898176 |
14 | 24bc33a7cb45d |
15 | 105a28b140c2d |
hex | 78fb4822a82b |
133020642355243 has 2 divisors, whose sum is σ = 133020642355244. Its totient is φ = 133020642355242.
The previous prime is 133020642355199. The next prime is 133020642355273. The reversal of 133020642355243 is 342553246020331.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133020642355243 - 237 = 132883203401771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 133020642355243.
It is not a weakly prime, because it can be changed into another prime (133020642355273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510321177621 + 66510321177622.
It is an arithmetic number, because the mean of its divisors is an integer number (66510321177622).
Almost surely, 2133020642355243 is an apocalyptic number.
133020642355243 is a deficient number, since it is larger than the sum of its proper divisors (1).
133020642355243 is an equidigital number, since it uses as much as digits as its factorization.
133020642355243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 133020642355243 its reverse (342553246020331), we get a palindrome (475573888375574).
The spelling of 133020642355243 in words is "one hundred thirty-three trillion, twenty billion, six hundred forty-two million, three hundred fifty-five thousand, two hundred forty-three".
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