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133020642355243 is a prime number
BaseRepresentation
bin11110001111101101001000…
…001000101010100000101011
3122102222122112021111212012121
4132033231020020222200223
5114413402233420331433
61150524501154452111
740006265344116346
oct3617551010524053
9572878467455177
10133020642355243
113942581284aa25
1212b0435bb94037
13592ba3c898176
1424bc33a7cb45d
15105a28b140c2d
hex78fb4822a82b

133020642355243 has 2 divisors, whose sum is σ = 133020642355244. Its totient is φ = 133020642355242.

The previous prime is 133020642355199. The next prime is 133020642355273. The reversal of 133020642355243 is 342553246020331.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 133020642355243 - 237 = 132883203401771 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 133020642355243.

It is not a weakly prime, because it can be changed into another prime (133020642355273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510321177621 + 66510321177622.

It is an arithmetic number, because the mean of its divisors is an integer number (66510321177622).

Almost surely, 2133020642355243 is an apocalyptic number.

133020642355243 is a deficient number, since it is larger than the sum of its proper divisors (1).

133020642355243 is an equidigital number, since it uses as much as digits as its factorization.

133020642355243 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1555200, while the sum is 43.

Adding to 133020642355243 its reverse (342553246020331), we get a palindrome (475573888375574).

The spelling of 133020642355243 in words is "one hundred thirty-three trillion, twenty billion, six hundred forty-two million, three hundred fifty-five thousand, two hundred forty-three".