Base | Representation |
---|---|
bin | 11110001111101101011111… |
… | …010111100011111011111101 |
3 | 122102222200112102221210111102 |
4 | 132033231133113203323331 |
5 | 114413404033211331240 |
6 | 1150525004001102445 |
7 | 40006311116160605 |
oct | 3617553727437375 |
9 | 572880472853442 |
10 | 133021032136445 |
11 | 394259a2876352 |
12 | 12b0444a627a25 |
13 | 592baa256c42b |
14 | 24bc376491c05 |
15 | 105a2b0486815 |
hex | 78fb5f5e3efd |
133021032136445 has 16 divisors (see below), whose sum is σ = 159701755023360. Its totient is φ = 106365820828800.
The previous prime is 133021032136409. The next prime is 133021032136457. The reversal of 133021032136445 is 544631230120331.
It is not a de Polignac number, because 133021032136445 - 210 = 133021032135421 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133021032136399 and 133021032136408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 178296740 + ... + 179041250.
It is an arithmetic number, because the mean of its divisors is an integer number (9981359688960).
Almost surely, 2133021032136445 is an apocalyptic number.
It is an amenable number.
133021032136445 is a deficient number, since it is larger than the sum of its proper divisors (26680722886915).
133021032136445 is a wasteful number, since it uses less digits than its factorization.
133021032136445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 761596.
The product of its (nonzero) digits is 155520, while the sum is 38.
Adding to 133021032136445 its reverse (544631230120331), we get a palindrome (677652262256776).
The spelling of 133021032136445 in words is "one hundred thirty-three trillion, twenty-one billion, thirty-two million, one hundred thirty-six thousand, four hundred forty-five".
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