Base | Representation |
---|---|
bin | 11110001111101101100100… |
… | …000100110010011011101001 |
3 | 122102222200201221112121201112 |
4 | 132033231210010302123221 |
5 | 114413404213420214121 |
6 | 1150525015501400105 |
7 | 40006313065312463 |
oct | 3617554404623351 |
9 | 572880657477645 |
10 | 133021111101161 |
11 | 39425a333aa748 |
12 | 12b04470b69035 |
13 | 592bab5a2950a |
14 | 24bc382b69133 |
15 | 105a2b738375b |
hex | 78fb641326e9 |
133021111101161 has 2 divisors, whose sum is σ = 133021111101162. Its totient is φ = 133021111101160.
The previous prime is 133021111101157. The next prime is 133021111101209. The reversal of 133021111101161 is 161101111120331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 132647277907600 + 373833193561 = 11517260^2 + 611419^2 .
It is a cyclic number.
It is not a de Polignac number, because 133021111101161 - 22 = 133021111101157 is a prime.
It is not a weakly prime, because it can be changed into another prime (133021111101101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510555550580 + 66510555550581.
It is an arithmetic number, because the mean of its divisors is an integer number (66510555550581).
Almost surely, 2133021111101161 is an apocalyptic number.
It is an amenable number.
133021111101161 is a deficient number, since it is larger than the sum of its proper divisors (1).
133021111101161 is an equidigital number, since it uses as much as digits as its factorization.
133021111101161 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 23.
Adding to 133021111101161 its reverse (161101111120331), we get a palindrome (294122222221492).
The spelling of 133021111101161 in words is "one hundred thirty-three trillion, twenty-one billion, one hundred eleven million, one hundred one thousand, one hundred sixty-one".
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