Base | Representation |
---|---|
bin | 111101111100010101… |
… | …1010110011000101011 |
3 | 110201100110201200001212 |
4 | 1323320223112120223 |
5 | 4134411402213311 |
6 | 141035320303335 |
7 | 12416246653223 |
oct | 1737053263053 |
9 | 421313650055 |
10 | 133021132331 |
11 | 51460a6360a |
12 | 21944611b4b |
13 | c70ba779b9 |
14 | 661c813083 |
15 | 36d81cdc8b |
hex | 1ef8ad662b |
133021132331 has 2 divisors, whose sum is σ = 133021132332. Its totient is φ = 133021132330.
The previous prime is 133021132297. The next prime is 133021132369. The reversal of 133021132331 is 133231120331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133021132331 - 222 = 133016938027 is a prime.
It is a super-2 number, since 2×1330211323312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133021132297 and 133021132306.
It is not a weakly prime, because it can be changed into another prime (133021132631) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66510566165 + 66510566166.
It is an arithmetic number, because the mean of its divisors is an integer number (66510566166).
Almost surely, 2133021132331 is an apocalyptic number.
133021132331 is a deficient number, since it is larger than the sum of its proper divisors (1).
133021132331 is an equidigital number, since it uses as much as digits as its factorization.
133021132331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 133021132331 its reverse (133231120331), we get a palindrome (266252252662).
The spelling of 133021132331 in words is "one hundred thirty-three billion, twenty-one million, one hundred thirty-two thousand, three hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.067 sec. • engine limits •