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13302121043401 is a prime number
BaseRepresentation
bin1100000110010010010000…
…1100110001010111001001
31202002200002200112201120121
43001210210030301113021
53220420220441342101
644142524323023241
72542021650164041
oct301444414612711
952080080481517
1013302121043401
1142694415a8323
1215aa05950ab21
13756500062198
1433db7cb30721
151810431680a1
hexc19243315c9

13302121043401 has 2 divisors, whose sum is σ = 13302121043402. Its totient is φ = 13302121043400.

The previous prime is 13302121043399. The next prime is 13302121043411. The reversal of 13302121043401 is 10434012120331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13273627603401 + 28493440000 = 3643299^2 + 168800^2 .

It is a cyclic number.

It is not a de Polignac number, because 13302121043401 - 21 = 13302121043399 is a prime.

Together with 13302121043399, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13302121043411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651060521700 + 6651060521701.

It is an arithmetic number, because the mean of its divisors is an integer number (6651060521701).

Almost surely, 213302121043401 is an apocalyptic number.

It is an amenable number.

13302121043401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13302121043401 is an equidigital number, since it uses as much as digits as its factorization.

13302121043401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13302121043401 its reverse (10434012120331), we get a palindrome (23736133163732).

The spelling of 13302121043401 in words is "thirteen trillion, three hundred two billion, one hundred twenty-one million, forty-three thousand, four hundred one".