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1330213220981 is a prime number
BaseRepresentation
bin10011010110110110111…
…000101111001001110101
311201011111211212002210122
4103112312320233021311
5133243234041032411
62455031433501325
7165050631550631
oct23266670571165
94634454762718
101330213220981
1147315a759307
12195979871845
13985916c54a8
1448550057dc1
152490661a9db
hex135b6e2f275

1330213220981 has 2 divisors, whose sum is σ = 1330213220982. Its totient is φ = 1330213220980.

The previous prime is 1330213220971. The next prime is 1330213220989. The reversal of 1330213220981 is 1890223120331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1260376702225 + 69836518756 = 1122665^2 + 264266^2 .

It is a cyclic number.

It is not a de Polignac number, because 1330213220981 - 226 = 1330146112117 is a prime.

It is a super-2 number, since 2×13302132209812 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1330213220989) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665106610490 + 665106610491.

It is an arithmetic number, because the mean of its divisors is an integer number (665106610491).

Almost surely, 21330213220981 is an apocalyptic number.

It is an amenable number.

1330213220981 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330213220981 is an equidigital number, since it uses as much as digits as its factorization.

1330213220981 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 1330213220981 in words is "one trillion, three hundred thirty billion, two hundred thirteen million, two hundred twenty thousand, nine hundred eighty-one".