Base | Representation |
---|---|
bin | 11110001111101111010110… |
… | …001001110111001111011110 |
3 | 122102222212200022221111021121 |
4 | 132033233112021313033132 |
5 | 114413422123402043311 |
6 | 1150525533431521154 |
7 | 40006411365422266 |
oct | 3617572611671736 |
9 | 572885608844247 |
10 | 133023025034206 |
11 | 3942682580199a |
12 | 12b04905b291ba |
13 | 592c02c3cab88 |
14 | 24bc4c501c7a6 |
15 | 105a37a3e4b71 |
hex | 78fbd62773de |
133023025034206 has 4 divisors (see below), whose sum is σ = 199534537551312. Its totient is φ = 66511512517102.
The previous prime is 133023025034177. The next prime is 133023025034311. The reversal of 133023025034206 is 602430520320331.
It is a semiprime because it is the product of two primes.
It is a super-3 number, since 3×1330230250342063 (a number of 43 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33255756258550 + ... + 33255756258553.
It is an arithmetic number, because the mean of its divisors is an integer number (49883634387828).
Almost surely, 2133023025034206 is an apocalyptic number.
133023025034206 is a deficient number, since it is larger than the sum of its proper divisors (66511512517106).
133023025034206 is an equidigital number, since it uses as much as digits as its factorization.
133023025034206 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66511512517105.
The product of its (nonzero) digits is 77760, while the sum is 34.
Adding to 133023025034206 its reverse (602430520320331), we get a palindrome (735453545354537).
The spelling of 133023025034206 in words is "one hundred thirty-three trillion, twenty-three billion, twenty-five million, thirty-four thousand, two hundred six".
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