Search a number
-
+
133023163354573 is a prime number
BaseRepresentation
bin11110001111101111011110…
…011001100000110111001101
3122102222220000222012220011011
4132033233132121200313031
5114413422414304321243
61150525555252325221
740006414665215542
oct3617573631406715
9572886028186134
10133023163354573
1139426896897048
1212b04944313811
13592c051c6a84b
1424bc4d9546bc9
15105a38761889d
hex78fbde660dcd

133023163354573 has 2 divisors, whose sum is σ = 133023163354574. Its totient is φ = 133023163354572.

The previous prime is 133023163354541. The next prime is 133023163354603. The reversal of 133023163354573 is 375453361320331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80795325458884 + 52227837895689 = 8988622^2 + 7226883^2 .

It is a cyclic number.

It is not a de Polignac number, because 133023163354573 - 25 = 133023163354541 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133023163354273) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511581677286 + 66511581677287.

It is an arithmetic number, because the mean of its divisors is an integer number (66511581677287).

Almost surely, 2133023163354573 is an apocalyptic number.

It is an amenable number.

133023163354573 is a deficient number, since it is larger than the sum of its proper divisors (1).

133023163354573 is an equidigital number, since it uses as much as digits as its factorization.

133023163354573 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6123600, while the sum is 49.

The spelling of 133023163354573 in words is "one hundred thirty-three trillion, twenty-three billion, one hundred sixty-three million, three hundred fifty-four thousand, five hundred seventy-three".