Base | Representation |
---|---|
bin | 11110001111101111101000… |
… | …100011001011111011000111 |
3 | 122102222220110211200102120201 |
4 | 132033233220203023323013 |
5 | 114413423241404144112 |
6 | 1150530024214511331 |
7 | 40006422133626046 |
oct | 3617575043137307 |
9 | 572886424612521 |
10 | 133023333662407 |
11 | 39426973a39921 |
12 | 12b04991365547 |
13 | 592c07b32a006 |
14 | 24bc513dda55d |
15 | 105a39755a257 |
hex | 78fbe88cbec7 |
133023333662407 has 2 divisors, whose sum is σ = 133023333662408. Its totient is φ = 133023333662406.
The previous prime is 133023333662293. The next prime is 133023333662441. The reversal of 133023333662407 is 704266333320331.
It is a strong prime.
It is an emirp because it is prime and its reverse (704266333320331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133023333662407 - 215 = 133023333629639 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133023333662207) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66511666831203 + 66511666831204.
It is an arithmetic number, because the mean of its divisors is an integer number (66511666831204).
Almost surely, 2133023333662407 is an apocalyptic number.
133023333662407 is a deficient number, since it is larger than the sum of its proper divisors (1).
133023333662407 is an equidigital number, since it uses as much as digits as its factorization.
133023333662407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2939328, while the sum is 46.
Adding to 133023333662407 its reverse (704266333320331), we get a palindrome (837289666982738).
The spelling of 133023333662407 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred thirty-three million, six hundred sixty-two thousand, four hundred seven".
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