Base | Representation |
---|---|
bin | 11110001111101111101001… |
… | …001000110111011111111110 |
3 | 122102222220111112021021101201 |
4 | 132033233221020313133332 |
5 | 114413423301421241342 |
6 | 1150530025210330114 |
7 | 40006422313606252 |
oct | 3617575110673776 |
9 | 572886445237351 |
10 | 133023343540222 |
11 | 39426979576203 |
12 | 12b0499472993a |
13 | 592c0803a8085 |
14 | 24bc51544c262 |
15 | 105a39835bdb7 |
hex | 78fbe92377fe |
133023343540222 has 8 divisors (see below), whose sum is σ = 201365611781400. Its totient is φ = 65901472946424.
The previous prime is 133023343540211. The next prime is 133023343540223. The reversal of 133023343540222 is 222045343320331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×1330233435402222 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133023343540223) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 305099411572 + ... + 305099412007.
It is an arithmetic number, because the mean of its divisors is an integer number (25170701472675).
Almost surely, 2133023343540222 is an apocalyptic number.
133023343540222 is a deficient number, since it is larger than the sum of its proper divisors (68342268241178).
133023343540222 is a wasteful number, since it uses less digits than its factorization.
133023343540222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 610198823690.
The product of its (nonzero) digits is 311040, while the sum is 37.
Adding to 133023343540222 its reverse (222045343320331), we get a palindrome (355068686860553).
The spelling of 133023343540222 in words is "one hundred thirty-three trillion, twenty-three billion, three hundred forty-three million, five hundred forty thousand, two hundred twenty-two".
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