Base | Representation |
---|---|
bin | 11110001111110000011000… |
… | …001110011111111001010011 |
3 | 122102222222112120210200222111 |
4 | 132033300120032133321103 |
5 | 114413431411141424210 |
6 | 1150530235431050151 |
7 | 40006451015544640 |
oct | 3617603016377123 |
9 | 572888476720874 |
10 | 133024133545555 |
11 | 394272444aa97a |
12 | 12b04b75210957 |
13 | 592c177c6b955 |
14 | 24bc58c334dc7 |
15 | 105a3e28ac88a |
hex | 78fc1839fe53 |
133024133545555 has 8 divisors (see below), whose sum is σ = 182433097433952. Its totient is φ = 91216548716928.
The previous prime is 133024133545469. The next prime is 133024133545607. The reversal of 133024133545555 is 555545331420331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133024133545555 - 237 = 132886694592083 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133024133545499 and 133024133545508.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1900344764902 + ... + 1900344764971.
It is an arithmetic number, because the mean of its divisors is an integer number (22804137179244).
Almost surely, 2133024133545555 is an apocalyptic number.
133024133545555 is a deficient number, since it is larger than the sum of its proper divisors (49408963888397).
133024133545555 is an equidigital number, since it uses as much as digits as its factorization.
133024133545555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3800689529885.
The product of its (nonzero) digits is 8100000, while the sum is 49.
Adding to 133024133545555 its reverse (555545331420331), we get a palindrome (688569464965886).
The spelling of 133024133545555 in words is "one hundred thirty-three trillion, twenty-four billion, one hundred thirty-three million, five hundred forty-five thousand, five hundred fifty-five".
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