Base | Representation |
---|---|
bin | 11110001111110000011000… |
… | …001110100000111111011110 |
3 | 122102222222112120210221010211 |
4 | 132033300120032200333132 |
5 | 114413431411142100141 |
6 | 1150530235431123034 |
7 | 40006451015564014 |
oct | 3617603016407736 |
9 | 572888476727124 |
10 | 133024133550046 |
11 | 39427244503292 |
12 | 12b04b7521347a |
13 | 592c177c709cb |
14 | 24bc58c3368b4 |
15 | 105a3e28add81 |
hex | 78fc183a0fde |
133024133550046 has 4 divisors (see below), whose sum is σ = 199536200325072. Its totient is φ = 66512066775022.
The previous prime is 133024133550043. The next prime is 133024133550047. The reversal of 133024133550046 is 640055331420331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 133024133549990 and 133024133550008.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133024133550043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33256033387510 + ... + 33256033387513.
It is an arithmetic number, because the mean of its divisors is an integer number (49884050081268).
Almost surely, 2133024133550046 is an apocalyptic number.
133024133550046 is a deficient number, since it is larger than the sum of its proper divisors (66512066775026).
133024133550046 is an equidigital number, since it uses as much as digits as its factorization.
133024133550046 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66512066775025.
The product of its (nonzero) digits is 388800, while the sum is 40.
Adding to 133024133550046 its reverse (640055331420331), we get a palindrome (773079464970377).
The spelling of 133024133550046 in words is "one hundred thirty-three trillion, twenty-four billion, one hundred thirty-three million, five hundred fifty thousand, forty-six".
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