Base | Representation |
---|---|
bin | 111101111100011100… |
… | …0000001010110011011 |
3 | 110201100200222102121020 |
4 | 1323320320001112123 |
5 | 4134413230012133 |
6 | 141035515413523 |
7 | 12416320126425 |
oct | 1737070012633 |
9 | 421320872536 |
10 | 133024454043 |
11 | 51462922228 |
12 | 219457542a3 |
13 | c70c66b900 |
14 | 661d039815 |
15 | 36d86380b3 |
hex | 1ef8e0159b |
133024454043 has 24 divisors (see below), whose sum is σ = 194217006960. Its totient is φ = 80941386240.
The previous prime is 133024454041. The next prime is 133024454099. The reversal of 133024454043 is 340454420331.
It is not a de Polignac number, because 133024454043 - 21 = 133024454041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 133024453995 and 133024454013.
It is not an unprimeable number, because it can be changed into a prime (133024454041) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1428898 + ... + 1519143.
It is an arithmetic number, because the mean of its divisors is an integer number (8092375290).
Almost surely, 2133024454043 is an apocalyptic number.
133024454043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133024454043 is a deficient number, since it is larger than the sum of its proper divisors (61192552917).
133024454043 is a wasteful number, since it uses less digits than its factorization.
133024454043 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2948159 (or 2948146 counting only the distinct ones).
The product of its (nonzero) digits is 69120, while the sum is 33.
Adding to 133024454043 its reverse (340454420331), we get a palindrome (473478874374).
The spelling of 133024454043 in words is "one hundred thirty-three billion, twenty-four million, four hundred fifty-four thousand, forty-three".
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