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133025324020214 = 2411622260049027
BaseRepresentation
bin11110001111110001011111…
…001011110011000111110110
3122110000002121112220002012112
4132033301133023303013312
5114413441330422121324
61150530553515051022
740006522352451353
oct3617613713630766
9573002545802175
10133025324020214
11394277a54a012a
1212b05247a40a72
13592c3077a9622
1424bc6624a562a
15105a462165c0e
hex78fc5f2f31f6

133025324020214 has 8 divisors (see below), whose sum is σ = 204404766177528. Its totient is φ = 64890401961040.

The previous prime is 133025324020177. The next prime is 133025324020273. The reversal of 133025324020214 is 412020423520331.

133025324020214 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 811130024432 + ... + 811130024595.

It is an arithmetic number, because the mean of its divisors is an integer number (25550595772191).

Almost surely, 2133025324020214 is an apocalyptic number.

133025324020214 is a deficient number, since it is larger than the sum of its proper divisors (71379442157314).

133025324020214 is a wasteful number, since it uses less digits than its factorization.

133025324020214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1622260049070.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 133025324020214 its reverse (412020423520331), we get a palindrome (545045747540545).

The spelling of 133025324020214 in words is "one hundred thirty-three trillion, twenty-five billion, three hundred twenty-four million, twenty thousand, two hundred fourteen".

Divisors: 1 2 41 82 1622260049027 3244520098054 66512662010107 133025324020214