Base | Representation |
---|---|
bin | 11110001111110001011111… |
… | …001011110011110101100110 |
3 | 122110000002121112220020012222 |
4 | 132033301133023303311212 |
5 | 114413441330422220032 |
6 | 1150530553515112342 |
7 | 40006522352463035 |
oct | 3617613713636546 |
9 | 573002545806188 |
10 | 133025324023142 |
11 | 394277a54a2351 |
12 | 12b05247a426b2 |
13 | 592c3077aaa65 |
14 | 24bc6624a671c |
15 | 105a462166a12 |
hex | 78fc5f2f3d66 |
133025324023142 has 8 divisors (see below), whose sum is σ = 202348380204432. Its totient is φ = 65575863955000.
The previous prime is 133025324023129. The next prime is 133025324023147. The reversal of 133025324023142 is 241320423520331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133025324023147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 468399028109 + ... + 468399028392.
It is an arithmetic number, because the mean of its divisors is an integer number (25293547525554).
Almost surely, 2133025324023142 is an apocalyptic number.
133025324023142 is a deficient number, since it is larger than the sum of its proper divisors (69323056181290).
133025324023142 is an equidigital number, since it uses as much as digits as its factorization.
133025324023142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 936798056574.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 133025324023142 its reverse (241320423520331), we get a palindrome (374345747543473).
The spelling of 133025324023142 in words is "one hundred thirty-three trillion, twenty-five billion, three hundred twenty-four million, twenty-three thousand, one hundred forty-two".
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