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133025324061113 = 11105553111456993
BaseRepresentation
bin11110001111110001011111…
…001011111101000110111001
3122110000002121112222011022022
4132033301133023331012321
5114413441330424423423
61150530553520004225
740006522353011531
oct3617613713750671
9573002545864268
10133025324061113
11394277a5518930
1212b05247a60675
13592c3077c2123
1424bc6624b64c1
15105a462172dc8
hex78fc5f2fd1b9

133025324061113 has 8 divisors (see below), whose sum is σ = 145118685489696. Its totient is φ = 120931987657600.

The previous prime is 133025324061103. The next prime is 133025324061163. The reversal of 133025324061113 is 311160423520331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133025324061113 - 222 = 133025319866809 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (133025324061103) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5882345 + ... + 17339337.

It is an arithmetic number, because the mean of its divisors is an integer number (18139835686212).

Almost surely, 2133025324061113 is an apocalyptic number.

It is an amenable number.

133025324061113 is a deficient number, since it is larger than the sum of its proper divisors (12093361428583).

133025324061113 is a wasteful number, since it uses less digits than its factorization.

133025324061113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12512535.

The product of its (nonzero) digits is 38880, while the sum is 35.

Adding to 133025324061113 its reverse (311160423520331), we get a palindrome (444185747581444).

The spelling of 133025324061113 in words is "one hundred thirty-three trillion, twenty-five billion, three hundred twenty-four million, sixty-one thousand, one hundred thirteen".

Divisors: 1 11 1055531 11456993 11610841 126026923 12093211278283 133025324061113