133025505061241 has 4 divisors (see below), whose sum is σ = 143258236219812. Its totient is φ = 122792773902672.

The previous prime is 133025505061157. The next prime is 133025505061243. The reversal of 133025505061241 is 142160505520331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 63809677705216 + 69215827356025 = 7988096^2 + 8319605^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133025505061241 is a prime.

It is a super-3 number, since 3×133025505061241³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133025505061195 and 133025505061204.

It is not an unprimeable number, because it can be changed into a prime (133025505061243) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5116365579266 + ... + 5116365579291.

It is an arithmetic number, because the mean of its divisors is an integer number (35814559054953).

Almost surely, 2^{133025505061241} is an apocalyptic number.

It is an amenable number.

133025505061241 is a deficient number, since it is larger than the sum of its proper divisors (10232731158571).

133025505061241 is a wasteful number, since it uses less digits than its factorization.

133025505061241 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10232731158570.

The product of its (nonzero) digits is 108000, while the sum is 38.

The spelling of 133025505061241 in words is "one hundred thirty-three trillion, twenty-five billion, five hundred five million, sixty-one thousand, two hundred forty-one".