Base | Representation |
---|---|
bin | 111101111100100110… |
… | …1010101001010111011 |
3 | 110201101002111020102211 |
4 | 1323321031111022323 |
5 | 4134421142242001 |
6 | 141040235235551 |
7 | 12416415453643 |
oct | 1737115251273 |
9 | 421332436384 |
10 | 133030040251 |
11 | 51465a98229 |
12 | 219475a8bb7 |
13 | c710876464 |
14 | 661da91523 |
15 | 36d8d8d351 |
hex | 1ef93552bb |
133030040251 has 4 divisors (see below), whose sum is σ = 137321331904. Its totient is φ = 128738748600.
The previous prime is 133030040219. The next prime is 133030040257. The reversal of 133030040251 is 152040030331.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 152040030331 = 7 ⋅21720004333.
It is a cyclic number.
It is not a de Polignac number, because 133030040251 - 25 = 133030040219 is a prime.
It is not an unprimeable number, because it can be changed into a prime (133030040257) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2145645780 + ... + 2145645841.
It is an arithmetic number, because the mean of its divisors is an integer number (34330332976).
Almost surely, 2133030040251 is an apocalyptic number.
133030040251 is a deficient number, since it is larger than the sum of its proper divisors (4291291653).
133030040251 is an equidigital number, since it uses as much as digits as its factorization.
133030040251 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4291291652.
The product of its (nonzero) digits is 1080, while the sum is 22.
Adding to 133030040251 its reverse (152040030331), we get a palindrome (285070070582).
The spelling of 133030040251 in words is "one hundred thirty-three billion, thirty million, forty thousand, two hundred fifty-one".
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