Base | Representation |
---|---|
bin | 1100000110010101100111… |
… | …1110100110111100110001 |
3 | 1202002202102120022010111112 |
4 | 3001211121332212330301 |
5 | 3220424042431103101 |
6 | 44143154033323105 |
7 | 2542053214222652 |
oct | 301453176467461 |
9 | 52082376263445 |
10 | 13303023300401 |
11 | 426986493136a |
12 | 15aa26b706495 |
13 | 756614c68c73 |
14 | 33dc268b7529 |
15 | 18109748d6bb |
hex | c1959fa6f31 |
13303023300401 has 2 divisors, whose sum is σ = 13303023300402. Its totient is φ = 13303023300400.
The previous prime is 13303023300389. The next prime is 13303023300421. The reversal of 13303023300401 is 10400332030331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12908563936801 + 394459363600 = 3592849^2 + 628060^2 .
It is a cyclic number.
It is not a de Polignac number, because 13303023300401 - 218 = 13303023038257 is a prime.
It is not a weakly prime, because it can be changed into another prime (13303023300421) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651511650200 + 6651511650201.
It is an arithmetic number, because the mean of its divisors is an integer number (6651511650201).
Almost surely, 213303023300401 is an apocalyptic number.
It is an amenable number.
13303023300401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303023300401 is an equidigital number, since it uses as much as digits as its factorization.
13303023300401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 23.
Adding to 13303023300401 its reverse (10400332030331), we get a palindrome (23703355330732).
The spelling of 13303023300401 in words is "thirteen trillion, three hundred three billion, twenty-three million, three hundred thousand, four hundred one".
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