Base | Representation |
---|---|
bin | 1100000110010101111010… |
… | …1010110111101110101011 |
3 | 1202002202122001102002222012 |
4 | 3001211132222313232223 |
5 | 3220424223103343311 |
6 | 44143205524350135 |
7 | 2542055161242545 |
oct | 301453652675653 |
9 | 52082561362865 |
10 | 13303102012331 |
11 | 42698a530284a |
12 | 15aa291b4534b |
13 | 756628367c81 |
14 | 33dc33126695 |
15 | 18109e33a78b |
hex | c195eab7bab |
13303102012331 has 2 divisors, whose sum is σ = 13303102012332. Its totient is φ = 13303102012330.
The previous prime is 13303102012297. The next prime is 13303102012337. The reversal of 13303102012331 is 13321020130331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13303102012331 - 214 = 13303101995947 is a prime.
It is a super-2 number, since 2×133031020123312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13303102012297 and 13303102012306.
It is not a weakly prime, because it can be changed into another prime (13303102012337) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651551006165 + 6651551006166.
It is an arithmetic number, because the mean of its divisors is an integer number (6651551006166).
Almost surely, 213303102012331 is an apocalyptic number.
13303102012331 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303102012331 is an equidigital number, since it uses as much as digits as its factorization.
13303102012331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 23.
Adding to 13303102012331 its reverse (13321020130331), we get a palindrome (26624122142662).
The spelling of 13303102012331 in words is "thirteen trillion, three hundred three billion, one hundred two million, twelve thousand, three hundred thirty-one".
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