Base | Representation |
---|---|
bin | 11000110001110110… |
… | …10110100110001001 |
3 | 1021100010011012212102 |
4 | 30120323112212021 |
5 | 204221044122441 |
6 | 10040015523145 |
7 | 650443414163 |
oct | 143073264611 |
9 | 37303135772 |
10 | 13303114121 |
11 | 57072965a0 |
12 | 26b32294b5 |
13 | 134012007b |
14 | 902b0d933 |
15 | 52cd7869b |
hex | 318ed6989 |
13303114121 has 16 divisors (see below), whose sum is σ = 14857793280. Its totient is φ = 11806282320.
The previous prime is 13303114073. The next prime is 13303114147. The reversal of 13303114121 is 12141130331.
13303114121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13303114121 is a prime.
It is a super-3 number, since 3×133031141213 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13303114093 and 13303114102.
It is not an unprimeable number, because it can be changed into a prime (13303111121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1054670 + ... + 1067208.
It is an arithmetic number, because the mean of its divisors is an integer number (928612080).
Almost surely, 213303114121 is an apocalyptic number.
13303114121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13303114121 is a deficient number, since it is larger than the sum of its proper divisors (1554679159).
13303114121 is a wasteful number, since it uses less digits than its factorization.
13303114121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14836.
The product of its (nonzero) digits is 216, while the sum is 20.
Adding to 13303114121 its reverse (12141130331), we get a palindrome (25444244452).
The spelling of 13303114121 in words is "thirteen billion, three hundred three million, one hundred fourteen thousand, one hundred twenty-one".
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