Base | Representation |
---|---|
bin | 111101111100101001… |
… | …1000100011001010111 |
3 | 110201101012022122202022 |
4 | 1323321103010121113 |
5 | 4134422033410112 |
6 | 141040331403355 |
7 | 12416434320146 |
oct | 1737123043127 |
9 | 421335278668 |
10 | 133031544407 |
11 | 51466925333 |
12 | 21947bb355b |
13 | c710c81ca8 |
14 | 661dd6375d |
15 | 36d9088d72 |
hex | 1ef94c4657 |
133031544407 has 2 divisors, whose sum is σ = 133031544408. Its totient is φ = 133031544406.
The previous prime is 133031544361. The next prime is 133031544449. The reversal of 133031544407 is 704445130331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 133031544407 - 212 = 133031540311 is a prime.
It is a super-2 number, since 2×1330315444072 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133031544487) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66515772203 + 66515772204.
It is an arithmetic number, because the mean of its divisors is an integer number (66515772204).
Almost surely, 2133031544407 is an apocalyptic number.
133031544407 is a deficient number, since it is larger than the sum of its proper divisors (1).
133031544407 is an equidigital number, since it uses as much as digits as its factorization.
133031544407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 60480, while the sum is 35.
Adding to 133031544407 its reverse (704445130331), we get a palindrome (837476674738).
The spelling of 133031544407 in words is "one hundred thirty-three billion, thirty-one million, five hundred forty-four thousand, four hundred seven".
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