Base | Representation |
---|---|
bin | 1100000110010110011100… |
… | …0101111011001110110101 |
3 | 1202002202222220022101210111 |
4 | 3001211213011323032311 |
5 | 3220430020242303133 |
6 | 44143231533223021 |
7 | 2542061525330131 |
oct | 301454705731665 |
9 | 52082886271714 |
10 | 13303243322293 |
11 | 426996804a041 |
12 | 15aa311331a71 |
13 | 75664b713632 |
14 | 33dc47bcc3c1 |
15 | 1810ab9501cd |
hex | c196717b3b5 |
13303243322293 has 2 divisors, whose sum is σ = 13303243322294. Its totient is φ = 13303243322292.
The previous prime is 13303243322273. The next prime is 13303243322339. The reversal of 13303243322293 is 39222334230331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8763032698564 + 4540210623729 = 2960242^2 + 2130777^2 .
It is a cyclic number.
It is not a de Polignac number, because 13303243322293 - 229 = 13302706451381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13303243322203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6651621661146 + 6651621661147.
It is an arithmetic number, because the mean of its divisors is an integer number (6651621661147).
Almost surely, 213303243322293 is an apocalyptic number.
It is an amenable number.
13303243322293 is a deficient number, since it is larger than the sum of its proper divisors (1).
13303243322293 is an equidigital number, since it uses as much as digits as its factorization.
13303243322293 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 419904, while the sum is 40.
The spelling of 13303243322293 in words is "thirteen trillion, three hundred three billion, two hundred forty-three million, three hundred twenty-two thousand, two hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •