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1330334402101 = 3142914012971
BaseRepresentation
bin10011010110111110000…
…111000000011000110101
311201011211021212202001021
4103112332013000120311
5133244011101331401
62455051443101141
7165053632561435
oct23267607003065
94634737782037
101330334402101
114732120a74a1
121959b23717b1
13985b0843bb3
14485621a02c5
15249120a62a1
hex135be1c0635

1330334402101 has 4 divisors (see below), whose sum is σ = 1373248415104. Its totient is φ = 1287420389100.

The previous prime is 1330334402077. The next prime is 1330334402119. The reversal of 1330334402101 is 1012044330331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1330334402101 - 27 = 1330334401973 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1330334402171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21457006455 + ... + 21457006516.

It is an arithmetic number, because the mean of its divisors is an integer number (343312103776).

Almost surely, 21330334402101 is an apocalyptic number.

It is an amenable number.

1330334402101 is a deficient number, since it is larger than the sum of its proper divisors (42914013003).

1330334402101 is an equidigital number, since it uses as much as digits as its factorization.

1330334402101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 42914013002.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 1330334402101 its reverse (1012044330331), we get a palindrome (2342378732432).

The spelling of 1330334402101 in words is "one trillion, three hundred thirty billion, three hundred thirty-four million, four hundred two thousand, one hundred one".

Divisors: 1 31 42914012971 1330334402101