Base | Representation |
---|---|
bin | 10011010110111110000… |
… | …111000000011000110101 |
3 | 11201011211021212202001021 |
4 | 103112332013000120311 |
5 | 133244011101331401 |
6 | 2455051443101141 |
7 | 165053632561435 |
oct | 23267607003065 |
9 | 4634737782037 |
10 | 1330334402101 |
11 | 4732120a74a1 |
12 | 1959b23717b1 |
13 | 985b0843bb3 |
14 | 485621a02c5 |
15 | 249120a62a1 |
hex | 135be1c0635 |
1330334402101 has 4 divisors (see below), whose sum is σ = 1373248415104. Its totient is φ = 1287420389100.
The previous prime is 1330334402077. The next prime is 1330334402119. The reversal of 1330334402101 is 1012044330331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1330334402101 - 27 = 1330334401973 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1330334402171) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21457006455 + ... + 21457006516.
It is an arithmetic number, because the mean of its divisors is an integer number (343312103776).
Almost surely, 21330334402101 is an apocalyptic number.
It is an amenable number.
1330334402101 is a deficient number, since it is larger than the sum of its proper divisors (42914013003).
1330334402101 is an equidigital number, since it uses as much as digits as its factorization.
1330334402101 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 42914013002.
The product of its (nonzero) digits is 2592, while the sum is 25.
Adding to 1330334402101 its reverse (1012044330331), we get a palindrome (2342378732432).
The spelling of 1330334402101 in words is "one trillion, three hundred thirty billion, three hundred thirty-four million, four hundred two thousand, one hundred one".
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