Base | Representation |
---|---|
bin | 11110001111111001111100… |
… | …010010011001010000011110 |
3 | 122110000222001020010120110022 |
4 | 132033321330102121100132 |
5 | 114414113423432120014 |
6 | 1150535054412312142 |
7 | 40010263335062306 |
oct | 3617717422312036 |
9 | 573028036116408 |
10 | 133034402223134 |
11 | 39430633945375 |
12 | 12b06b60172652 |
13 | 593012350b029 |
14 | 24bcc84036606 |
15 | 105a7e413da8e |
hex | 78fe7c49941e |
133034402223134 has 4 divisors (see below), whose sum is σ = 199551603334704. Its totient is φ = 66517201111566.
The previous prime is 133034402223131. The next prime is 133034402223157. The reversal of 133034402223134 is 431322204430331.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 133034402223094 and 133034402223103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (133034402223131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33258600555782 + ... + 33258600555785.
It is an arithmetic number, because the mean of its divisors is an integer number (49887900833676).
Almost surely, 2133034402223134 is an apocalyptic number.
133034402223134 is a deficient number, since it is larger than the sum of its proper divisors (66517201111570).
133034402223134 is an equidigital number, since it uses as much as digits as its factorization.
133034402223134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66517201111569.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 133034402223134 its reverse (431322204430331), we get a palindrome (564356606653465).
The spelling of 133034402223134 in words is "one hundred thirty-three trillion, thirty-four billion, four hundred two million, two hundred twenty-three thousand, one hundred thirty-four".
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