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133034402223134 = 266517201111567
BaseRepresentation
bin11110001111111001111100…
…010010011001010000011110
3122110000222001020010120110022
4132033321330102121100132
5114414113423432120014
61150535054412312142
740010263335062306
oct3617717422312036
9573028036116408
10133034402223134
1139430633945375
1212b06b60172652
13593012350b029
1424bcc84036606
15105a7e413da8e
hex78fe7c49941e

133034402223134 has 4 divisors (see below), whose sum is σ = 199551603334704. Its totient is φ = 66517201111566.

The previous prime is 133034402223131. The next prime is 133034402223157. The reversal of 133034402223134 is 431322204430331.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 133034402223094 and 133034402223103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133034402223131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33258600555782 + ... + 33258600555785.

It is an arithmetic number, because the mean of its divisors is an integer number (49887900833676).

Almost surely, 2133034402223134 is an apocalyptic number.

133034402223134 is a deficient number, since it is larger than the sum of its proper divisors (66517201111570).

133034402223134 is an equidigital number, since it uses as much as digits as its factorization.

133034402223134 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66517201111569.

The product of its (nonzero) digits is 124416, while the sum is 35.

Adding to 133034402223134 its reverse (431322204430331), we get a palindrome (564356606653465).

The spelling of 133034402223134 in words is "one hundred thirty-three trillion, thirty-four billion, four hundred two million, two hundred twenty-three thousand, one hundred thirty-four".

Divisors: 1 2 66517201111567 133034402223134