Base | Representation |
---|---|
bin | 10011010110111111000… |
… | …010111011110110011001 |
3 | 11201011212101102220012001 |
4 | 103112333002323312121 |
5 | 133244024112042103 |
6 | 2455053203521001 |
7 | 165054213242356 |
oct | 23267702736631 |
9 | 4634771386161 |
10 | 1330350112153 |
11 | 47321aa57707 |
12 | 1959b7689161 |
13 | 985b3b8479a |
14 | 485642cd62d |
15 | 2491365b01d |
hex | 135bf0bbd99 |
1330350112153 has 2 divisors, whose sum is σ = 1330350112154. Its totient is φ = 1330350112152.
The previous prime is 1330350112139. The next prime is 1330350112159. The reversal of 1330350112153 is 3512110530331.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1006273809424 + 324076302729 = 1003132^2 + 569277^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1330350112153 is a prime.
It is not a weakly prime, because it can be changed into another prime (1330350112159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665175056076 + 665175056077.
It is an arithmetic number, because the mean of its divisors is an integer number (665175056077).
Almost surely, 21330350112153 is an apocalyptic number.
It is an amenable number.
1330350112153 is a deficient number, since it is larger than the sum of its proper divisors (1).
1330350112153 is an equidigital number, since it uses as much as digits as its factorization.
1330350112153 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4050, while the sum is 28.
Adding to 1330350112153 its reverse (3512110530331), we get a palindrome (4842460642484).
The spelling of 1330350112153 in words is "one trillion, three hundred thirty billion, three hundred fifty million, one hundred twelve thousand, one hundred fifty-three".
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