13303623105142 has 4 divisors (see below), whose sum is σ = 19955434657716. Its totient is φ = 6651811552570.

The previous prime is 13303623105107. The next prime is 13303623105167. The reversal of 13303623105142 is 24150132630331.

It is a semiprime because it is the product of two primes.

It is a super-3 number, since 3×13303623105142³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13303623105098 and 13303623105107.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3325905776284 + ... + 3325905776287.

It is an arithmetic number, because the mean of its divisors is an integer number (4988858664429).

Almost surely, 2^{13303623105142} is an apocalyptic number.

13303623105142 is a deficient number, since it is larger than the sum of its proper divisors (6651811552574).

13303623105142 is an equidigital number, since it uses as much as digits as its factorization.

13303623105142 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6651811552573.

The product of its (nonzero) digits is 38880, while the sum is 34.

Adding to 13303623105142 its reverse (24150132630331), we get a palindrome (37453755735473).

The spelling of 13303623105142 in words is "thirteen trillion, three hundred three billion, six hundred twenty-three million, one hundred five thousand, one hundred forty-two".