Base | Representation |
---|---|
bin | 111101111100111001… |
… | …1010111010001011011 |
3 | 110201101210020202211001 |
4 | 1323321303113101123 |
5 | 4134431220312311 |
6 | 141041233045431 |
7 | 12416566300144 |
oct | 1737163272133 |
9 | 421353222731 |
10 | 133040010331 |
11 | 51470687968 |
12 | 2194a9b6877 |
13 | c712957507 |
14 | 6621128acb |
15 | 36d9bac4c1 |
hex | 1ef9cd745b |
133040010331 has 2 divisors, whose sum is σ = 133040010332. Its totient is φ = 133040010330.
The previous prime is 133040010319. The next prime is 133040010361. The reversal of 133040010331 is 133010040331.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133040010331 is a prime.
It is a super-2 number, since 2×1330400103312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133040010299 and 133040010308.
It is not a weakly prime, because it can be changed into another prime (133040010361) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66520005165 + 66520005166.
It is an arithmetic number, because the mean of its divisors is an integer number (66520005166).
Almost surely, 2133040010331 is an apocalyptic number.
133040010331 is a deficient number, since it is larger than the sum of its proper divisors (1).
133040010331 is an equidigital number, since it uses as much as digits as its factorization.
133040010331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 19.
Adding to 133040010331 its reverse (133010040331), we get a palindrome (266050050662).
The spelling of 133040010331 in words is "one hundred thirty-three billion, forty million, ten thousand, three hundred thirty-one".
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