Base | Representation |
---|---|
bin | 11110001111111111001101… |
… | …001110100010000110001000 |
3 | 122110001111122012002010100210 |
4 | 132033333031032202012020 |
5 | 114414212013103220202 |
6 | 1150541431350001120 |
7 | 40010553406031631 |
oct | 3617771516420610 |
9 | 573044565063323 |
10 | 133040055132552 |
11 | 39432a74858937 |
12 | 12b080793461a0 |
13 | 59308146cbc49 |
14 | 24bd25cad4888 |
15 | 105aa25564c6c |
hex | 78ffcd3a2188 |
133040055132552 has 32 divisors (see below), whose sum is σ = 332600502376800. Its totient is φ = 44346636438144.
The previous prime is 133040055132487. The next prime is 133040055132563. The reversal of 133040055132552 is 255231550040331.
It is a super-3 number, since 3×1330400551325523 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 133040055132552.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 24356724 + ... + 29314332.
It is an arithmetic number, because the mean of its divisors is an integer number (10393765699275).
Almost surely, 2133040055132552 is an apocalyptic number.
133040055132552 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
133040055132552 is an abundant number, since it is smaller than the sum of its proper divisors (199560447244248).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133040055132552 is a wasteful number, since it uses less digits than its factorization.
133040055132552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6075765 (or 6075761 counting only the distinct ones).
The product of its (nonzero) digits is 270000, while the sum is 39.
The spelling of 133040055132552 in words is "one hundred thirty-three trillion, forty billion, fifty-five million, one hundred thirty-two thousand, five hundred fifty-two".
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