Base | Representation |
---|---|
bin | 11110001111111111010001… |
… | …010001110111001010000000 |
3 | 122110001111210220222221112100 |
4 | 132033333101101313022000 |
5 | 114414212133004122422 |
6 | 1150541442215030400 |
7 | 40010555162620614 |
oct | 3617772121671200 |
9 | 573044726887470 |
10 | 133040123114112 |
11 | 39432aaa170445 |
12 | 12b0809806b400 |
13 | 5930825811b16 |
14 | 24bd267b4d344 |
15 | 105aa2b4e27ac |
hex | 78ffd1477280 |
133040123114112 has 288 divisors, whose sum is σ = 404156393372160. Its totient is φ = 42001255296000.
The previous prime is 133040123114053. The next prime is 133040123114149. The reversal of 133040123114112 is 211411321040331.
133040123114112 is a `hidden beast` number, since 1 + 3 + 3 + 0 + 401 + 231 + 14 + 1 + 12 = 666.
It is a tau number, because it is divible by the number of its divisors (288).
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 1601481537 + ... + 1601564607.
It is an arithmetic number, because the mean of its divisors is an integer number (1403320810320).
Almost surely, 2133040123114112 is an apocalyptic number.
133040123114112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 133040123114112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (202078196686080).
133040123114112 is an abundant number, since it is smaller than the sum of its proper divisors (271116270258048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133040123114112 is a wasteful number, since it uses less digits than its factorization.
133040123114112 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 86980 (or 86946 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 27.
Adding to 133040123114112 its reverse (211411321040331), we get a palindrome (344451444154443).
The spelling of 133040123114112 in words is "one hundred thirty-three trillion, forty billion, one hundred twenty-three million, one hundred fourteen thousand, one hundred twelve".
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