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1330402331201 is a prime number
BaseRepresentation
bin10011010111000010001…
…010001000101001000001
311201012000000200220020212
4103113002022020221001
5133244130444044301
62455102311043505
7165055416141446
oct23270212105101
94635000626225
101330402331201
11473247483649
12195a11070595
13985c1938c28
144856b2039cd
15249180234bb
hex135c2288a41

1330402331201 has 2 divisors, whose sum is σ = 1330402331202. Its totient is φ = 1330402331200.

The previous prime is 1330402331197. The next prime is 1330402331207. The reversal of 1330402331201 is 1021332040331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1000398039601 + 330004291600 = 1000199^2 + 574460^2 .

It is an emirp because it is prime and its reverse (1021332040331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1330402331201 - 22 = 1330402331197 is a prime.

It is not a weakly prime, because it can be changed into another prime (1330402331207) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665201165600 + 665201165601.

It is an arithmetic number, because the mean of its divisors is an integer number (665201165601).

Almost surely, 21330402331201 is an apocalyptic number.

It is an amenable number.

1330402331201 is a deficient number, since it is larger than the sum of its proper divisors (1).

1330402331201 is an equidigital number, since it uses as much as digits as its factorization.

1330402331201 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1330402331201 its reverse (1021332040331), we get a palindrome (2351734371532).

The spelling of 1330402331201 in words is "one trillion, three hundred thirty billion, four hundred two million, three hundred thirty-one thousand, two hundred one".